900x^2+50090x-2000=0

Solution for 900x^2+50090x-2000=0 equation:

900x^2+50090x-2000=0

a = 900; b = 50090; c = -2000;
Δ = b2-4ac
Δ = 500902-4·900·(-2000)
Δ = 2516208100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2516208100}=\sqrt{100*25162081}=\sqrt{100}*\sqrt{25162081}=10\sqrt{25162081}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50090)-10\sqrt{25162081}}{2*900}=\frac{-50090-10\sqrt{25162081}}{1800}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50090)+10\sqrt{25162081}}{2*900}=\frac{-50090+10\sqrt{25162081}}{1800}
$